```
```6)One third of three fifth of two seventh of a number is 30. What will be 20% of that number

A) 140

B) 120

C) 180

D) 200

**Answer:**A) 120

**Explanation:**(1/3)*(3/5)*(2/7)*a=30

=>a=30/0.05=600

20% of 600 =120

```
```7) What percent is 120 of 90? ?

A) 133 1/3%

B) 132 2/3%

C) 132 1/3%

D) None of these

**Answer:**A) 133 1/3%

**Explanation:** 120/90 = 4/3

4/3 × 100 = 400/3 = 133 1/3 %

```
```8) Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. What are the marks obtained by them ?

A) 43, 30

B) 42, 39

C) 42, 33

D) 44, 36

**Answer:**C) 42, 33

**Explanation:**Let the marks secured by the two students are x and (x + 9)

Then sum of their marks = x + (x + 9) = 2x + 9

Given that (x + 9) was 56% of the sum of their marks

=>(x+9) = 56/100(2x+9)

=>(x+9) = 14/25(2x+9)

=> 25x + 225 = 28x + 126

=> 3x = 99

=> x = 33

Then (x + 9) = 33 + 9 = 42

Hence their marks are 33 and 42

```
```9) Three candidates contested an election and received 1136, 7636 and 11628 votes respectively. What percentage of the total votes did the winning candidate get ?

A) 51%

B) 57%

C) 69%

D) 84%

**Answer:**B) 57%

**Explanation:**Total number of votes polled = (1136 + 7636 + 11628) = 20400.

Percentage that winning candidate get from total number of votes = (11628 / 20400 x 100)% = 57%.
.

```
```10) The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:

A) 10%

B) 3%

C) 21%

D) 5%

**Answer:**D) 5%

**Explanation:** Increase in 10 years = (262500 - 175000) = 87500

Increase percentage = (87500/175000 x 100) % = 50%

Hence, Required average = (50/10) % = 5%.